(4x-5)/(x^2-36)-3/(x+6)

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Solution for (4x-5)/(x^2-36)-3/(x+6) equation:


D( x )

x^2-36 = 0

x+6 = 0

x^2-36 = 0

x^2-36 = 0

1*x^2 = 36 // : 1

x^2 = 36

x^2 = 36 // ^ 1/2

abs(x) = 6

x = 6 or x = -6

x+6 = 0

x+6 = 0

x+6 = 0 // - 6

x = -6

x in (-oo:-6) U (-6:6) U (6:+oo)

(4*x-5)/(x^2-36)-(3/(x+6)) = 0

(4*x-5)/(x^2-36)-3*(x+6)^-1 = 0

(4*x-5)/(x^2-36)-3/(x+6) = 0

((4*x-5)*(x+6))/((x^2-36)*(x+6))+(-3*(x^2-36))/((x^2-36)*(x+6)) = 0

(4*x-5)*(x+6)-3*(x^2-36) = 0

x^2+19*x+78 = 0

x^2+19*x+78 = 0

x^2+19*x+78 = 0

DELTA = 19^2-(1*4*78)

DELTA = 49

DELTA > 0

x = (49^(1/2)-19)/(1*2) or x = (-49^(1/2)-19)/(1*2)

x = -6 or x = -13

(x+13)*(x+6) = 0

((x+13)*(x+6))/((x^2-36)*(x+6)) = 0

((x+13)*(x+6))/((x^2-36)*(x+6)) = 0 // * (x^2-36)*(x+6)

(x+13)*(x+6) = 0

( x+13 )

x+13 = 0 // - 13

x = -13

( x+6 )

x+6 = 0 // - 6

x = -6

x in { -6}

x = -13

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